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Vol.3 , No. 2, Publication Date: Jul. 29, 2016, Page: 17-25
 to (59) I consider (a) as a fixed exponent, and verify that a =0.5. From equation (60) onward I view (a) as a parameter (a <0.5) and arrive at a contradiction. At the end of the proof (from equation (73)) and through the assumption that (a) is a parameter, I verify again that a = 0.5.&picture=http://www.aascit.org/aascit/decorators/img/journal/921.jpg)
| [1] | Fayez Fok Al Adeh, President: The Syrian Cosmological Society, Damascus, Syria. |
I have already discovered a simple proof of the Riemann Hypothesis. The hypothesis states that the nontrivial zeros of the Riemann zeta function have real part equal to 0.5. I assume that any such zero is s =a+ bi. I use integral calculus in the first part of the proof. In the second part I employ variational calculus. Through equations (50) to (59) I consider (a) as a fixed exponent, and verify that a =0.5. From equation (60) onward I view (a) as a parameter (a <0.5) and arrive at a contradiction. At the end of the proof (from equation (73)) and through the assumption that (a) is a parameter, I verify again that a = 0.5.
Keywords
Definite Integrel, Indefinite Integral, Variational Calculus
Reference
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| [05] | Koblits, Neal (1984) “P- adic Numbers, P – adic Analysis, and Zeta – Functions”, New York: Springer – Verlag. |
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